for example, 0th position goes to 1st position and vice versa. while getting the response of same data, i am getting the order mismatch. problem statement : Posting an array of data from excel. To ensure both lists have exactly the same set of elements regardless of order, we can sort both. is there any way to ignore the order while comparing the json.
And the great thing about this is that the diff document can then be merged with the first JSON document that has been compared, yielding the second JSON document that has been compared. Compare two List objects for equality, ignoring order. The approach described in the other post focus in producing a JSON document that represents the differences between the two documents that have been compared.
#Json compare ignore order how to
I recently put together another post describing how to compare JSON documents using JSON-P. Quoting the RFC 8259, the document that defines the JSON format (highlights are mine):Īn object is an unordered collection of zero or more name/value pairs, where a name is a string and a value is a string, number, boolean, null, object, or array.Īn array is an ordered sequence of zero or more values. Never - The property is always serialized and deserialized, regardless of the DefaultIgnoreCondition, IgnoreReadOnlyProperties, and IgnoreReadOnlyFields global settings. If no Condition is specified, this option is assumed. This comparison method doesn’t take into account the order of the properties of objects, but it does take into account the order of the elements in arrays. The JsonIgnoreCondition enum provides the following options: Always - The property is always ignored. Since there are a variety of JSON libraries for Java (Jackson, GSON, json-lib, etc. It will produce the following output: Entries only on left Optionally, you may (1) allow any-order arrays and (2) ignore extra fields. println ( "\n\nEntries in common\n-" ) difference. println ( "\n\nEntries differing\n-" ) difference. println ( "\n\nEntries only on right\n-" ) difference. I want to compare two JSON strings in Java 8 for equality, but ignore specific known nodes which contain values which are expected to be different and are a. println ( "Entries only on left\n-" ) difference. You could try recursing over the deserialized structure, turning lists into some sort of multiset and dicts into some sort of hashable, frozen dict (so you can put them into multisets), then running your own diff routine on that. difference ( leftFlatMap, rightFlatMap ) System. Creating JSON Values Normalization, Merging, and Autowrapping of JSON Values Searching and Modifying JSON Values JSON Path Syntax Comparison and Ordering of. I don't know of any tools that will ignore order for you.
flatten ( rightMap ) MapDifference difference = Maps.
flatten ( leftMap ) Map rightFlatMap = FlatMapUtil. It uses the JSON Pointer notation defined in the RFC 6901 for the keys, so I can easily locate the values. Import import import import import import import public final class FlatMapUtil
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